Java binary to decimal conversion

shamzi097 · Jan 24th 2023

I have to create a software that converts bits to decimal. When I enter a bit, it merely returns 0.0. I'm at a loss as to why. I know it's really easy, but I'm not seeing it. Any assistance would be much appreciated.

Java

import java.lang.Math;
import java.util.Scanner;


public class Lab1 {
    static double number = 0;

    public static double toDec(String num) {

        char[] charArray = num.toCharArray();

        for(int i = 0; i<charArray.length;i++) {
            if(charArray[i] == 1) {
                number = Math.pow(2, charArray.length-i);
            }
        }

        return number;


    }


    public static void main(String[] args) {
        Scanner keyboard = new Scanner(System.in);
        int bit;
        String bitString;

        System.out.println("Please enter a bit");
        bit = keyboard.nextInt();
        bitString = Integer.toString(bit);


        System.out.println(toDec(bitString));



    }

}

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Tell · Jan 24th 2023

Java

import java.util.Scanner ;

public class Convert
{
   public static void main( String[] args )
   {
      Scanner scanner = new Scanner( System.in ) ;
      int     value   = 0 ;

      System.out.print( "Please enter a binary number: ") ;

      if( scanner.hasNext() )
      {
         String binary = scanner.next() ;

         for( int i = 0; i < binary.length(); i++ )
         {
            value <<= 1 ;

            if( binary.charAt(i) == '1' )
            {
               value |= 1 ;
            }
         }
      }

      System.out.println( "value: " + value ) ;
   }
}

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__blackjack__ · Jan 25th 2023

shamzi097 Somehow I don't get why there is a question at all because the link contains several solutions to the problem. Or was the real intention to place this link here, i.e. link spam‽

Simplest solution may be this one:

Java

import java.util.Scanner;

public final class Test {
    private Test() {}

    public static void main(String... args) {
        System.out.println(Integer.parseInt(new Scanner(System.in).next(), 2));
    }
}

Tell Alle Zeichen ausser 1 als 0 anzusehen ist ein bisschen unsauber IMHO.

shamzi097 · Feb 8th 2023

Quote from __blackjack__
shamzi097 Somehow I don't get why there is a question at all because the link contains several solutions to the problem. Or was the real intention to place this link here, i.e. link spam‽
(I know i just did not get the question so just wanted to get solution in detail thats all and about the link i put is because i wanted to share the source where i read about it and i am doing course from here thats why, thanks for your help)

Simplest solution may be this one:
Java
import java.util.Scanner;

public final class Test {
    private Test() {}

    public static void main(String... args) {
        System.out.println(Integer.parseInt(new Scanner(System.in).next(), 2));
    }
}
Tell Alle Zeichen ausser 1 als 0 anzusehen ist ein bisschen unsauber IMHO.

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